(b^2+3b-9)/(b+5)

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Solution for (b^2+3b-9)/(b+5) equation:


D( b )

b+5 = 0

b+5 = 0

b+5 = 0

b+5 = 0 // - 5

b = -5

b in (-oo:-5) U (-5:+oo)

(b^2+3*b-9)/(b+5) = 0

b^2+3*b-9 = 0

b^2+3*b-9 = 0

DELTA = 3^2-(-9*1*4)

DELTA = 45

DELTA > 0

b = (45^(1/2)-3)/(1*2) or b = (-45^(1/2)-3)/(1*2)

b = (3*5^(1/2)-3)/2 or b = (-3*5^(1/2)-3)/2

(b-((-3*5^(1/2)-3)/2))*(b-((3*5^(1/2)-3)/2)) = 0

((b-((-3*5^(1/2)-3)/2))*(b-((3*5^(1/2)-3)/2)))/(b+5) = 0

( b-((-3*5^(1/2)-3)/2) )

b-((-3*5^(1/2)-3)/2) = 0 // + (-3*5^(1/2)-3)/2

b = (-3*5^(1/2)-3)/2

( b-((3*5^(1/2)-3)/2) )

b-((3*5^(1/2)-3)/2) = 0 // + (3*5^(1/2)-3)/2

b = (3*5^(1/2)-3)/2

b in { (-3*5^(1/2)-3)/2, (3*5^(1/2)-3)/2 }

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